2+7z^2=4z

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Solution for 2+7z^2=4z equation: 



2+7z^2=4z

We move all terms to the left:

2+7z^2-(4z)=0

a = 7; b = -4; c = +2;
Δ = b2-4ac
Δ = -42-4·7·2
Δ = -40
Delta is less than zero, so there is no solution for the equation

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